0=x^2-160x+1500

Solution for 0=x^2-160x+1500 equation:

0=x^2-160x+1500

We move all terms to the left:

0-(x^2-160x+1500)=0

We add all the numbers together, and all the variables

-(x^2-160x+1500)=0

We get rid of parentheses

-x^2+160x-1500=0

We add all the numbers together, and all the variables

-1x^2+160x-1500=0

a = -1; b = 160; c = -1500;
Δ = b2-4ac
Δ = 1602-4·(-1)·(-1500)
Δ = 19600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{19600}=140$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(160)-140}{2*-1}=\frac{-300}{-2}
=+150
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(160)+140}{2*-1}=\frac{-20}{-2}
=+10
$